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7y^2+34y-5=0
a = 7; b = 34; c = -5;
Δ = b2-4ac
Δ = 342-4·7·(-5)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-36}{2*7}=\frac{-70}{14} =-5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+36}{2*7}=\frac{2}{14} =1/7 $
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